15b^2-29b+12=

Solution for 15b^2-29b+12= equation:

Simplifying
15b2 + -29b + 12 = 0

Reorder the terms:
12 + -29b + 15b2 = 0

Solving
12 + -29b + 15b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(3 + -5b)(4 + -3b) = 0

Subproblem 1
Set the factor '(3 + -5b)' equal to zero and attempt to solve:

Simplifying
3 + -5b = 0

Solving
3 + -5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -5b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -5b = 0 + -3
-5b = 0 + -3

Combine like terms: 0 + -3 = -3
-5b = -3

Divide each side by '-5'.
b = 0.6

Simplifying
b = 0.6
Subproblem 2
Set the factor '(4 + -3b)' equal to zero and attempt to solve:

Simplifying
4 + -3b = 0

Solving
4 + -3b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -3b = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -3b = 0 + -4
-3b = 0 + -4

Combine like terms: 0 + -4 = -4
-3b = -4

Divide each side by '-3'.
b = 1.333333333

Simplifying
b = 1.333333333
Solution
b = {0.6, 1.333333333}